WebMar 19, 2024 · In an AP: (i) given a = 8, an = 62. Sn = 210, find ‘n’ and ‘d’. (ii) given an = 4, d = 2, Sn = -14. find ‘n’ and a. (iii) given a = 3, n = 8, S = 192, find ‘d’. (iv) given L = 28, S = 144 and there are total 9 terms. Find ‘a’. arithmetic progression class-10 1 Answer +1 vote answered Mar 19, 2024 by Sunil01 (67.7k points) WebAug 26, 2024 · The sum of the first n terms of an AP is given by Sn, = 3n^2 - 4n. Determine the AP and the 12th term. asked Feb 1, 2024 in Mathematics by Kundan kumar ( 51.5k points)
In an AP, if Sₙ = n(4n + 1), find the AP - Cuemath
WebMay 5, 2024 · Solution: We have, a = 50, d=-4 and S n = 0 We know that S n = n/2 [2a+ (n−1)d] 0 = n/2 [2.50+ (n−1) (-4)] 0 = n/2 [100+ (-4n+4)] 0 = n/2 (104-4n) 4n = 104 n = 104/4 n = 26 Related questions 0 votes 1 answer If an AP is Sn = n (4n+1), then find the AP asked May 5, 2024 in Class X Maths by kabita (13.8k points) class-10 0 votes 1 answer WebAug 27, 2024 · The nth term of an Arithmetic progression is 4 . Common difference of the Arithmetic progression is 2 . The sum of the n terms of the Arithmetic progression is - 14 . This implies ; Using the formula , to find the nth term of the AP ! = a + ( n - 1 ) d }= 4 d = 2 4 = a + ( n - 1 )24 = a + 2n - 2 4 + 2 = a +2n 6 = a + 2n a + 2n = 6 equation−1 greentea mad gaming league of legends
In an AP, given a = 2 , d = 8 , Sn = 90 , find n and an - Toppr
WebNov 28, 2024 · An arithmetic progression (AP) is a sequence of numbers in which the difference between the consecutive terms is constant. If a is the first term, d is the common difference, and s_n is the... WebOct 25, 2024 · In an AP: (i) given a = 5, d = 3, an = 50, find n and Sn. (ii) given a = 7, a13 = 35, find d and S13. (iii) given a12 = 37, d = 3, find a and S12. (iv) given a3 = 15, S10 = 125, find d and a10. (v) given d = 5, S9 = 75, find a and a9 (vi) given a = 2, d = 8, Sn = 90, find n and an (vii) given a = 8, an = 62, Sn = 210, find n and d. (viii) given ... WebSolution Given that, an = 4, d = 2, Sn = −14 an = a + ( n − 1) d 4 = a + ( n − 1)2 4 = a + 2 n − 2 a + 2 n = 6 a = 6 − 2 n (i) S n = n 2 [ a + a n] - 14 = n 2 [ a + 4] −28 = n ( a + 4) −28 = n (6 − 2 n … fnb bank scottsboro alabama