WebI am trying to get the specific statement type name when parsing MySQL, using the Antlr4 generated C++ parser. I am using the MySQL Antlr4 grammar from here. This is what I am using right now: rule_index=SelectStatement()->getRuleIndex(); statement_type=getRuleNames()[rule_index]; Webstd::type_info:: name. std::type_info:: name. Returns an implementation defined null-terminated character string containing the name of the type. No guarantees are given; in …

typeid operator in C++ with Examples - GeeksforGeeks

WebJul 3, 2012 · The short answer is, you don't really need/want to know the type of a variable to use it. If you need to give a type to a static variable, then you may simply use auto. In more sophisticated case where you want to use "auto" in a class or struct, I would … WebC++11 The copy and assignment operators of type_info are private: objects of this type cannot be copied. Member functions operator== Compare types (public member … give away usb

c++ - How do I get the Antlr 4 rule name in C++? - STACKOOM

WebInside a declaration or a definition of a template, typename can be used to declare that a dependent qualified name is a type. Inside a declaration or a definition of a template, … WebThe example demonstrates std::any visitor idiom with ability to register new visitors at compile- and run-time. Run this code. #include #include #include … WebHere, you will get the above error because C++ grammar considered the variable declaration as a function call. The coding block for the above scenario has been attached below: #include using namespace std; int main () { int age (); cout << “Please enter your age here: “; cin >> age; cin.ignore (); cout << “Your age is: “<< age <<“n”; furniture village warrington cheshire